Questions: 36. x is directly proportional to the cube of y. x=3 when y=7. What is x when y=14? x=
1. 24
2. 196
3. 12
4. 21
37. 8x+27+3y=27y+3; x=
1. 13y+3
2. 3y-3
3. 3y
4. 6
Transcript text: 36. x is directly proportional to the cube of y . $\mathrm{x}=3$ when $\mathrm{y}=7$. What is x when $\mathrm{y}=14$ ? $\mathrm{x}=$
1
24
2
196
3
12
4
21
37. $8 x+27+3 y=27 y+3 ; \quad x=$
1
$13 y+3$
2
$3 y-3$
3
$3 y$
4
6
Solution
Solution Steps
Solution Approach
For the equation \(8 + 7 = 5x - 15\), solve for \(x\) by isolating it on one side of the equation.
For the problem where \(x\) is directly proportional to the cube of \(y\), use the proportionality relationship to find the constant of proportionality and then calculate \(x\) for \(y = 14\).
For the equation \(8x + 27 + 3y = 27y + 3\), rearrange the terms to solve for \(x\) in terms of \(y\).
Step 1: Solve the Equation \(8 + 7 = 5x - 15\)
Starting with the equation:
\[
8 + 7 = 5x - 15
\]
we simplify it to:
\[
15 = 5x - 15
\]
Adding 15 to both sides gives:
\[
30 = 5x
\]
Dividing both sides by 5 results in:
\[
x = 6
\]
Step 2: Find \(x\) When \(y = 14\) Given \(x\) is Proportional to \(y^3\)
Given that \(x\) is directly proportional to the cube of \(y\), we can express this as:
\[
x = k y^3
\]
where \(k\) is the constant of proportionality. We know that \(x = 3\) when \(y = 7\):
\[
3 = k (7^3) \implies k = \frac{3}{343} \approx 0.008746355685131196
\]
Now, substituting \(y = 14\):
\[
x = k (14^3) = 0.008746355685131196 \times 2744 = 24.0
\]