Questions: Question 18
2 pts
Consider the unbalanced equation shown below.
H2SO4(aq) + Al(OH)3(s) -> H2O(l) + Al2(SO4)3(aq)
When the equation above is balanced using the smallest whole-number coefficients, the coefficient for water will be:
2
6
1
3
Transcript text: Question 18
2 pts
Consider the unbalanced equation shown below.
\[
\ldots \mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\ldots \mathrm{Al}(\mathrm{OH})_{3}(\mathrm{~s}) \longrightarrow \ldots \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\ldots \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)
\]
When the equation above is balanced using the smallest whole-number coefficients, the coefficient for water will be:
2
6
1
3
We need to balance the following atoms: hydrogen (H), sulfur (S), oxygen (O), and aluminum (Al).
Step 3: Balance Aluminum Atoms
There are 2 aluminum atoms in \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\). Therefore, we need 2 \(\mathrm{Al}(\mathrm{OH})_{3}\) on the reactant side:
Now, balance the hydrogen and oxygen atoms. Each \(\mathrm{Al}(\mathrm{OH})_{3}\) provides 3 \(\mathrm{OH}^{-}\) groups, so 2 \(\mathrm{Al}(\mathrm{OH})_{3}\) provides 6 \(\mathrm{OH}^{-}\) groups, which combine with 6 hydrogen atoms from \(\mathrm{H}_{2} \mathrm{SO}_{4}\) to form 6 \(\mathrm{H}_{2} \mathrm{O}\):