Questions: For f(x)=5x-9 and g(x)=(1/5)(x+9), find (f ∘ g)(x) and (g ∘ f)(x). Then determine whether (f ∘ g)(x)=(g ∘ f)(x). What is (f ∘ g)(x)?

For f(x)=5x-9 and g(x)=(1/5)(x+9), find (f ∘ g)(x) and (g ∘ f)(x). Then determine whether (f ∘ g)(x)=(g ∘ f)(x).

What is (f ∘ g)(x)?
Transcript text: For $f(x)=5 x-9$ and $g(x)=\frac{1}{5}(x+9)$, find $(f \circ g)(x)$ and $(g \circ f)(x)$. Then determine whether $(f \circ g)(x)=(g \circ f)(x)$. What is $(f \circ g)(x)$ ?
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Solution

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Solution Steps

Step 1: Understand the Composition of Functions

The composition of two functions \( f \) and \( g \) is denoted as \( (f \circ g)(x) \), which means \( f(g(x)) \). Similarly, \( (g \circ f)(x) \) means \( g(f(x)) \).

Step 2: Find \( (f \circ g)(x) \)

Given:

  • \( f(x) = 5x - 9 \)
  • \( g(x) = \frac{1}{5}(x + 9) \)

To find \( (f \circ g)(x) \), substitute \( g(x) \) into \( f(x) \):

\[ (f \circ g)(x) = f(g(x)) = f\left(\frac{1}{5}(x + 9)\right) \]

Substitute \( \frac{1}{5}(x + 9) \) into \( f(x) = 5x - 9 \):

\[ f\left(\frac{1}{5}(x + 9)\right) = 5\left(\frac{1}{5}(x + 9)\right) - 9 \]

Simplify the expression:

\[ = (x + 9) - 9 \]

\[ = x \]

Step 3: Find \( (g \circ f)(x) \)

To find \( (g \circ f)(x) \), substitute \( f(x) \) into \( g(x) \):

\[ (g \circ f)(x) = g(f(x)) = g(5x - 9) \]

Substitute \( 5x - 9 \) into \( g(x) = \frac{1}{5}(x + 9) \):

\[ g(5x - 9) = \frac{1}{5}((5x - 9) + 9) \]

Simplify the expression:

\[ = \frac{1}{5}(5x) \]

\[ = x \]

Step 4: Determine if \( (f \circ g)(x) = (g \circ f)(x) \)

From the calculations above, we have:

\[ (f \circ g)(x) = x \]

\[ (g \circ f)(x) = x \]

Since both compositions result in \( x \), we conclude that \( (f \circ g)(x) = (g \circ f)(x) \).

Final Answer

\[ (f \circ g)(x) = \boxed{x} \]

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