Questions: Let g(x)=-2(3x+4)(x-1)(x-3)^2 be a polynomial function.
a. Find all the roots/zeros/x-intercepts.
b. Find the y-intercept of g.
Transcript text: Let $g(x)=-2(3 x+4)(x-1)(x-3)^{2}$ be a polynomial function.
a. Find all the roots/zeros/x-intercepts.
b. Find the $y$-intercept of $g$.
Solution
Solution Steps
To solve the given polynomial function \( g(x) = -2(3x + 4)(x - 1)(x - 3)^2 \):
a. To find the roots/zeros/x-intercepts, set \( g(x) = 0 \) and solve for \( x \).
b. To find the y-intercept, evaluate \( g(0) \).
Step 1: Finding the Roots/Zeros/X-Intercepts
To find the roots of the polynomial function \( g(x) = -2(3x + 4)(x - 1)(x - 3)^2 \), we set \( g(x) = 0 \). The roots are obtained from the factors of the polynomial:
From \( 3x + 4 = 0 \), we find \( x = -\frac{4}{3} \).
From \( x - 1 = 0 \), we find \( x = 1 \).
From \( (x - 3)^2 = 0 \), we find \( x = 3 \) (with a multiplicity of 2).
Thus, the roots are:
\[
x = -\frac{4}{3}, \quad x = 1, \quad x = 3
\]
Step 2: Finding the Y-Intercept
To find the y-intercept of the function \( g \), we evaluate \( g(0) \):
\[
g(0) = -2(3(0) + 4)(0 - 1)(0 - 3)^2 = -2(4)(-1)(9) = 72
\]
Final Answer
The roots of the polynomial are:
\[
\boxed{x = -\frac{4}{3}, \, 1, \, 3}
\]
The y-intercept of the function is:
\[
\boxed{72}
\]