Questions: Write a function to represent the display area in terms of (x). [ A(x)=36xy ] What dimensions should be used to maximize the display area? The dimensions should be (square) in by (square) in.

Write a function to represent the display area in terms of (x).
[ A(x)=36xy ]

What dimensions should be used to maximize the display area?

The dimensions should be (square) in by (square) in.
Transcript text: Write a function to represent the display area in terms of $x$. \[ A(x)=36 x y \] What dimensions should be used to maximize the display area? The dimensions should be $\square$ in by $\square$ in.
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Solution

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Solution Steps

Solution Approach

To maximize the display area, we need to find the critical points of the function \( A(x) = -x^2 + 18x \). This involves taking the derivative of \( A(x) \), setting it to zero, and solving for \( x \). Once we have \( x \), we can find the corresponding \( y \) value using the relationship between \( x \) and \( y \).

Step 1: Find the Critical Points

To maximize the display area \( A(x) = -x^2 + 18x \), we first find the derivative: \[ A'(x) = 18 - 2x \] Setting the derivative equal to zero to find critical points: \[ 18 - 2x = 0 \implies x = 9 \]

Step 2: Calculate the Corresponding \( y \) Value

Using the relationship between \( x \) and \( y \), we find \( y \) when \( x = 9 \): \[ y = \frac{36}{x} = \frac{36}{9} = 4 \]

Final Answer

The dimensions that should be used to maximize the display area are \( 9 \) in by \( 4 \) in. Thus, the final answer is: \[ \boxed{(9, 4)} \]

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