The given system of linear equations is: \[ x - 4y = 12 \] \[ 5x + 4y = -12 \]
First, we need to convert these equations into slope-intercept form \( y = mx + b \).
For the first equation: \[ x - 4y = 12 \] \[ -4y = -x + 12 \] \[ y = \frac{1}{4}x - 3 \]
For the second equation: \[ 5x + 4y = -12 \] \[ 4y = -5x - 12 \] \[ y = -\frac{5}{4}x - 3 \]
Next, we graph the two equations on the same coordinate plane.
For \( y = \frac{1}{4}x - 3 \):
For \( y = -\frac{5}{4}x - 3 \):
The solution to the system of equations is the point where the two lines intersect.
By graphing the equations, we observe that both lines intersect at the point \((0, -3)\).
The solution to the system of equations is: \[ (0, -3) \]
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