Questions: Chemical Reactions Predicting the products of a combustion reaction Predict the products of the following reaction. If no reaction will occur, use the NO REACTION button. Be sure your chemical equation is balanced! (CH2)3(OH)2(l) + O2(g) →

Chemical Reactions
Predicting the products of a combustion reaction

Predict the products of the following reaction. If no reaction will occur, use the NO REACTION button.
Be sure your chemical equation is balanced!

(CH2)3(OH)2(l) + O2(g) →
Transcript text: Chemical Reactions Predicting the products of a combustion reaction Predict the products of the following reaction. If no reaction will occur, use the NO REACTION button. Be sure your chemical equation is balanced! \[ \left(\mathrm{CH}_{2}\right)_{3}(\mathrm{OH})_{2}(\mathrm{l})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow \] $\square$
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Solution

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Solution Steps

Step 1: Identify the Type of Reaction

The given reaction involves a hydrocarbon-like compound, (CH2)3(OH)2(\mathrm{CH}_{2})_{3}(\mathrm{OH})_{2}, reacting with oxygen O2\mathrm{O}_{2}. This is a typical combustion reaction where an organic compound reacts with oxygen to produce carbon dioxide and water.

Step 2: Write the General Form of a Combustion Reaction

In a combustion reaction, a hydrocarbon or an alcohol reacts with oxygen to form carbon dioxide CO2\mathrm{CO}_{2} and water H2O\mathrm{H}_{2}\mathrm{O}. The general form is: Hydrocarbon/Alcohol+O2CO2+H2O \text{Hydrocarbon/Alcohol} + \mathrm{O}_{2} \rightarrow \mathrm{CO}_{2} + \mathrm{H}_{2}\mathrm{O}

Step 3: Determine the Products

For the given compound (CH2)3(OH)2(\mathrm{CH}_{2})_{3}(\mathrm{OH})_{2}, which can be rewritten as C3H8O2\mathrm{C}_{3}\mathrm{H}_{8}\mathrm{O}_{2}, the products of the combustion reaction will be carbon dioxide and water: C3H8O2+O2CO2+H2O \mathrm{C}_{3}\mathrm{H}_{8}\mathrm{O}_{2} + \mathrm{O}_{2} \rightarrow \mathrm{CO}_{2} + \mathrm{H}_{2}\mathrm{O}

Step 4: Balance the Chemical Equation

To balance the equation, ensure that the number of atoms of each element is the same on both sides of the equation.

  1. Carbon atoms: There are 3 carbon atoms in C3H8O2\mathrm{C}_{3}\mathrm{H}_{8}\mathrm{O}_{2}, so we need 3 CO2\mathrm{CO}_{2} molecules.
  2. Hydrogen atoms: There are 8 hydrogen atoms in C3H8O2\mathrm{C}_{3}\mathrm{H}_{8}\mathrm{O}_{2}, so we need 4 H2O\mathrm{H}_{2}\mathrm{O} molecules.
  3. Oxygen atoms: We have 3 CO2\mathrm{CO}_{2} and 4 H2O\mathrm{H}_{2}\mathrm{O}, which require 3×2+4=103 \times 2 + 4 = 10 oxygen atoms. The compound C3H8O2\mathrm{C}_{3}\mathrm{H}_{8}\mathrm{O}_{2} already provides 2 oxygen atoms, so we need 8 more from O2\mathrm{O}_{2}, which means 4 O2\mathrm{O}_{2} molecules.

The balanced equation is: C3H8O2+4O23CO2+4H2O \mathrm{C}_{3}\mathrm{H}_{8}\mathrm{O}_{2} + 4\mathrm{O}_{2} \rightarrow 3\mathrm{CO}_{2} + 4\mathrm{H}_{2}\mathrm{O}

Final Answer

C3H8O2+4O23CO2+4H2O \boxed{\mathrm{C}_{3}\mathrm{H}_{8}\mathrm{O}_{2} + 4\mathrm{O}_{2} \rightarrow 3\mathrm{CO}_{2} + 4\mathrm{H}_{2}\mathrm{O}}

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