Questions: Keisha's teacher gives her the following information:
- m, n, p, and q are all integers and p ≠ 0 and q ≠ 0
- A = m/q and B = n/p
What conclusion can Keisha make?
A · B = mp + nq/PV, so the product of two irrational numbers is an irrational number.
A + B = mp + np/p, so the sum of two rational numbers is a rational number.
A · B = mp + nq/N, so the product of two rational numbers is a rational number.
A + B = mp + nq/pP, so the sum of a rational number and an irrational number is an irrational number.
Transcript text: Keisha's teacher gives her the following information:
- $m, n, p$, and $q$ are all integers and $p \neq 0$ and $q \neq 0$
- $A=\frac{m}{q}$ and $B=\frac{n}{p}$
What conclusion can Keisha make?
$A \cdot B=\frac{m p+n q}{P V}$, so the product of two irrational numbers is an irrational number.
$A+B=\frac{m p+n_{p}}{p}$, so the sum of two rational numbers is a rational number.
$A \cdot B=\frac{m p+n q}{N}$, so the product of two rational numbers is a rational number.
$A+B=\frac{m p+n q}{p P}$, so the sum of a rational number and an irrational number is an irrational number.
Solution
Solution Steps
Step 1: Analyze the given information
We are given:
\( m, n, p, \) and \( q \) are integers with \( p \neq 0 \) and \( q \neq 0 \).
\( A = \frac{m}{q} \) and \( B = \frac{n}{p} \).
Since \( m, n, p, \) and \( q \) are integers and \( p, q \neq 0 \), both \( A \) and \( B \) are rational numbers.
Step 2: Evaluate the sum \( A + B \)
The sum of two rational numbers is:
\[
A + B = \frac{m}{q} + \frac{n}{p} = \frac{mp + nq}{pq}.
\]
Since \( mp + nq \) and \( pq \) are integers (as \( m, n, p, q \) are integers), \( A + B \) is a rational number.
Step 3: Evaluate the product \( A \cdot B \)
The product of two rational numbers is:
\[
A \cdot B = \frac{m}{q} \cdot \frac{n}{p} = \frac{mn}{pq}.
\]
Since \( mn \) and \( pq \) are integers (as \( m, n, p, q \) are integers), \( A \cdot B \) is a rational number.
Final Answer
The correct conclusion is:
\[
\boxed{A+B=\frac{mp+nq}{pq}, \text{ so the sum of two rational numbers is a rational number.}}
\]
and
\[
\boxed{A \cdot B=\frac{mn}{pq}, \text{ so the product of two rational numbers is a rational number.}}
\]