To solve the equation \(7(x+5)^{2} - 3 = 340\), we will first isolate the squared term by adding 3 to both sides and then dividing by 7. Next, we will take the square root of both sides to solve for \(x+5\). Finally, we will subtract 5 from both sides to solve for \(x\).
To solve the equation \(7(x+5)^{2} - 3 = 340\), we will follow these steps:
Step 1: Isolate the Squared Term
First, we need to isolate the term that contains the square. We start by adding 3 to both sides of the equation:
\[
7(x+5)^{2} - 3 + 3 = 340 + 3
\]
This simplifies to:
\[
7(x+5)^{2} = 343
\]
Step 2: Divide by the Coefficient of the Squared Term
Next, divide both sides of the equation by 7 to solve for \((x+5)^{2}\):
\[
\frac{7(x+5)^{2}}{7} = \frac{343}{7}
\]
This simplifies to:
\[
(x+5)^{2} = 49
\]
Step 3: Solve for \(x+5\) by Taking the Square Root
To solve for \(x+5\), take the square root of both sides. Remember that taking the square root introduces both a positive and a negative solution:
\[
x+5 = \pm \sqrt{49}
\]
This gives us:
\[
x+5 = \pm 7
\]
Step 4: Solve for \(x\)
Now, solve for \(x\) by subtracting 5 from both sides for each case: