Questions: Assume that a sample is used to estimate a population proportion μ. Find the margin of error M.E. that corresponds to a sample of size 57 with a mean of 82.9 and a standard deviation of 19.8 at a confidence level of 99.9%. Report ME accurate to one decimal place because the sample statistics are presented with this accuracy. M.E. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

Assume that a sample is used to estimate a population proportion μ. Find the margin of error M.E. that corresponds to a sample of size 57 with a mean of 82.9 and a standard deviation of 19.8 at a confidence level of 99.9%.

Report ME accurate to one decimal place because the sample statistics are presented with this accuracy.
M.E. =

Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Transcript text: Assume that a sample is used to estimate a population proportion $\mu$. Find the margin of error M.E. that corresponds to a sample of size 57 with a mean of 82.9 and a standard deviation of 19.8 at a confidence level of 99.9\%. Report ME accurate to one decimal place because the sample statistics are presented with this accuracy. M.E. = $\square$ Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
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Solution

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Solution Steps

Step 1: Determine the Z-Score

For a confidence level of \(99.9\%\), the corresponding Z-score is calculated to be \(Z = 3.3\).

Step 2: Calculate the Margin of Error

The formula for the margin of error (M.E.) is given by:

\[ \text{Margin of Error} = \frac{Z \times \sigma}{\sqrt{n}} \]

Substituting the known values:

  • \(Z = 3.3\)
  • \(\sigma = 19.8\)
  • \(n = 57\)

We can express the calculation as follows:

\[ \text{Margin of Error} = \frac{3.3 \times 19.8}{\sqrt{57}} \]

Step 3: Compute the Margin of Error

Calculating the above expression yields:

\[ \text{Margin of Error} \approx 8.6 \]

Final Answer

The margin of error (M.E.) is

\[ \boxed{8.6} \]

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