Questions: What is the intermediate step in the form (x+a)^2=b as a result are for the following equation? x^2-15 x+119=5 x-6

Solution Steps

We start with the equation:

\[ x^{2} - 15x + 119 = 5x - 6 \]

Rearranging this gives us:

\[ x^{2} - 20x + 125 = 0 \]

This can be expressed as:

\[ x^{2} - 20x = -125 \]

To complete the square, we take the coefficient of \(x\), which is \(-20\), divide it by \(2\) to get \(-10\), and then square it:

\[ \left(-10\right)^{2} = 100 \]

We add and subtract \(100\) to the left side of the equation:

\[ x^{2} - 20x + 100 = -125 + 100 \]

This simplifies to:

\[ (x - 10)^{2} = -25 \]

The completed square form of the equation is:

\[ 100.0 \left(0.1x - 1\right)^{2} - 100.0 = -125 \]

This indicates that the equation can be expressed as:

\[ (x - 10)^{2} = -25 \]

Final Answer