Questions: For -y-2x=-2 determine the value of y when x=0, and the value of x when y=0. Then graph the line using the identified intercepts.

For -y-2x=-2 determine the value of y when x=0, and the value of x when y=0. Then graph the line using the identified intercepts.
Transcript text: For $-y-2 x=-2$ determine the value of y when $\mathrm{x}=0$, and the value of x when $\mathrm{y}=0$. Then graph the line using the identified intercepts.
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Solution

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Solution Steps

Step 1: Determine the value of y when x = 0

To find the y-intercept, set \( x = 0 \) in the equation \( -y - 2x = -2 \): \[ -y - 2(0) = -2 \] \[ -y = -2 \] \[ y = 2 \]

Step 2: Determine the value of x when y = 0

To find the x-intercept, set \( y = 0 \) in the equation \( -y - 2x = -2 \): \[ -(0) - 2x = -2 \] \[ -2x = -2 \] \[ x = 1 \]

Step 3: Graph the line using the identified intercepts

Plot the points \((0, 2)\) and \((1, 0)\) on the graph. Draw a straight line through these points to represent the equation \( -y - 2x = -2 \).

Final Answer

  • y-intercept: \((0, 2)\)
  • x-intercept: \((1, 0)\)
  • Graph the line through these points.
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