Questions: A 1.05 L solution was made by mixing 462 mL of hexane, which has a density of 0.66 g / mL, and 0.61 L of toluene, which has a density of 0.87 g / mL. Calculate the volume percent of hexane in this solution.

Solution Steps

The volume of hexane is given as 462 mL. To convert this to liters, we use the conversion factor \(1 \, \text{L} = 1000 \, \text{mL}\):

\[ \text{Volume of hexane in liters} = \frac{462 \, \text{mL}}{1000} = 0.462 \, \text{L} \]

The total volume of the solution is given as 1.05 L.

The volume percent of hexane is calculated using the formula:

\[ \text{Volume percent of hexane} = \left( \frac{\text{Volume of hexane}}{\text{Total volume of solution}} \right) \times 100\% \]

Substituting the known values:

\[ \text{Volume percent of hexane} = \left( \frac{0.462 \, \text{L}}{1.05 \, \text{L}} \right) \times 100\% = 44.00\% \]

Final Answer