Questions: What is the equation of the line that goes through the points (0,2) and (1, 1)?
Transcript text: What is the equation of the line that goes through the points $(0,2)$ and $(1, 1)$?
Solution
Solution Steps
To find the equation of the line that goes through two points, we need to determine the slope and then use the point-slope form of the line equation. The slope \( m \) is calculated as the change in \( y \) divided by the change in \( x \). Once we have the slope, we can use one of the points to find the y-intercept \( b \) using the equation \( y = mx + b \).
Step 1: Calculate the Slope
To find the equation of the line passing through the points \((0, 2)\) and \((1, 1)\), we first calculate the slope \( m \). The slope is given by:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Substituting the given points:
\[
m = \frac{1 - 2}{1 - 0} = \frac{-1}{1} = -1.0
\]
Step 2: Calculate the Y-Intercept
Next, we use the slope \( m \) and one of the points to find the y-intercept \( b \). Using the point \((0, 2)\):
\[
y = mx + b
\]
Substituting \( x = 0 \), \( y = 2 \), and \( m = -1.0 \):
\[
2 = -1.0 \cdot 0 + b \implies b = 2.0
\]
Step 3: Form the Equation of the Line
With the slope \( m = -1.0 \) and the y-intercept \( b = 2.0 \), the equation of the line is:
\[
y = -1.0x + 2.0
\]
Final Answer
The equation of the line that goes through the points \((0, 2)\) and \((1, 1)\) is:
\[
\boxed{y = -x + 2}
\]