Questions: Question 7
Find the domain and range of (y=log 6(2+5 x)).
The domain is:
The range is :
Transcript text: Question 7
Find the domain and range of $y=\log _{6}(2+5 x)$.
The domain is: $\square$
The range is : $\square$
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Solution
Solution Steps
To find the domain and range of the function \( y = \log_{6}(2 + 5x) \):
Domain: The argument of the logarithm (inside the log function) must be greater than zero. So, solve the inequality \( 2 + 5x > 0 \) to find the domain.
Range: The logarithmic function can take any real number as its output, so the range is all real numbers.
Step 1: Determine the Domain
To find the domain of \( y = \log_{6}(2 + 5x) \), we need the argument of the logarithm to be greater than zero:
\[ 2 + 5x > 0 \]
Solving for \( x \):
\[ 5x > -2 \]
\[ x > -\frac{2}{5} \]
Thus, the domain is:
\[ x > -\frac{2}{5} \]
Step 2: Determine the Range
The range of a logarithmic function \( y = \log_{a}(x) \) for any base \( a > 1 \) is all real numbers. Therefore, the range of \( y = \log_{6}(2 + 5x) \) is:
\[ (-\infty, \infty) \]