Questions: Question 7 Find the domain and range of (y=log 6(2+5 x)). The domain is: The range is :

Question 7

Find the domain and range of (y=log 6(2+5 x)).
The domain is: 
The range is :
Transcript text: Question 7 Find the domain and range of $y=\log _{6}(2+5 x)$. The domain is: $\square$ The range is : $\square$ Question Help: Video Calculator Submit Question Jump to Answer
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Solution

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Solution Steps

To find the domain and range of the function \( y = \log_{6}(2 + 5x) \):

  1. Domain: The argument of the logarithm (inside the log function) must be greater than zero. So, solve the inequality \( 2 + 5x > 0 \) to find the domain.
  2. Range: The logarithmic function can take any real number as its output, so the range is all real numbers.
Step 1: Determine the Domain

To find the domain of \( y = \log_{6}(2 + 5x) \), we need the argument of the logarithm to be greater than zero: \[ 2 + 5x > 0 \] Solving for \( x \): \[ 5x > -2 \] \[ x > -\frac{2}{5} \] Thus, the domain is: \[ x > -\frac{2}{5} \]

Step 2: Determine the Range

The range of a logarithmic function \( y = \log_{a}(x) \) for any base \( a > 1 \) is all real numbers. Therefore, the range of \( y = \log_{6}(2 + 5x) \) is: \[ (-\infty, \infty) \]

Final Answer

The domain is: \[ \boxed{x > -\frac{2}{5}} \]

The range is: \[ \boxed{(-\infty, \infty)} \]

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