Questions: Tin (Sn) exists in Earth's crust as SnO2. Calculate the percent composition by mass of O and Sn in SnO2. Round your answer to 4 significant digits. Part 1 of 2 %O

Tin (Sn) exists in Earth's crust as SnO2. Calculate the percent composition by mass of O and Sn in SnO2. Round your answer to 4 significant digits.

Part 1 of 2
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Transcript text: $\mathrm{Tin}(\mathrm{Sn})$ exists in Earth's crust as $\mathrm{SnO}_{2}$. Calculate the percent composition by mass of O and Sn in $\mathrm{SnO}_{2}$. Round your answer to 4 significant digits. Part 1 of 2 $\square$ \%O $\square$口'

Solution

Solution Steps

Step 1: Determine the Molar Mass of Each Element

First, we need to find the molar mass of each element in $\mathrm{SnO}_{2}$.

The atomic mass of tin (Sn) is approximately 118.71 g/mol.
The atomic mass of oxygen (O) is approximately 16.00 g/mol.

Step 2: Calculate the Molar Mass of $\mathrm{SnO}_{2}$

Next, we calculate the molar mass of $\mathrm{SnO}_{2}$:

\[ \text{Molar mass of } \mathrm{SnO}_{2} = 118.71 \, \text{g/mol} + 2 \times 16.00 \, \text{g/mol} = 118.71 \, \text{g/mol} + 32.00 \, \text{g/mol} = 150.71 \, \text{g/mol} \]

Step 3: Calculate the Mass Percent of Each Element

Now, we calculate the mass percent of each element in $\mathrm{SnO}_{2}$.

Percent Composition of Oxygen (O)

\[ \% \text{O} = \left( \frac{2 \times 16.00 \, \text{g/mol}}{150.71 \, \text{g/mol}} \right) \times 100\% = \left( \frac{32.00}{150.71} \right) \times 100\% \approx 21.23\% \]

Percent Composition of Tin (Sn)

\[ \% \text{Sn} = \left( \frac{118.71 \, \text{g/mol}}{150.71 \, \text{g/mol}} \right) \times 100\% = \left( \frac{118.71}{150.71} \right) \times 100\% \approx 78.77\% \]