To solve the inequality \(3x - 3 > 3\), first add 3 to both sides to isolate the term with the variable: \[3x - 3 + 3 > 3 + 3\] \[3x > 6\]
Next, divide both sides by 3 to solve for \(x\): \[\frac{3x}{3} > \frac{6}{3}\] \[x > 2\]
The solution \(x > 2\) can be expressed in interval notation as: \[(2, \infty)\]
The solution to the inequality \(3x - 3 > 3\) is \(x > 2\), which in interval notation is \((2, \infty)\).
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