Questions: Consider the following frequency table representing the distribution of hours students watch TV in a week. Hours Students Watch TV in a Week Class Frequency ------ 12-16 7 17-21 7 22-26 7 27-31 8 32-36 4 Determine the lower class boundary for the fifth class.

Consider the following frequency table representing the distribution of hours students watch TV in a week.

Hours Students Watch TV in a Week

Class Frequency
------
12-16 7
17-21 7
22-26 7
27-31 8
32-36 4

Determine the lower class boundary for the fifth class.

Transcript text: Consider the following frequency table representing the distribution of hours students watch tv in a week. \begin{tabular}{|c|c|} \hline \multicolumn{2}{|c|}{ Hours Students } \\ \multicolumn{2}{|c|}{ Watch TV in a Week } \\ \hline Class & Frequency \\ \hline $12-16$ & 7 \\ \hline $17-21$ & 7 \\ \hline $22-26$ & 7 \\ \hline $27-31$ & 8 \\ \hline $32-36$ & 4 \\ \hline \end{tabular} Step 1 of 2: Determine the lower class boundary for the fifth class.

Solution

Solution Steps

To determine the lower class boundary for the fifth class, we need to understand that the class boundaries are the actual limits of the class intervals. The lower class boundary is found by subtracting 0.5 from the lower class limit of the interval.

For the fifth class, the interval is $32-36$. The lower class limit is 32. Therefore, the lower class boundary is 32 - 0.5.

Step 1: Identify the Lower Class Limit

The fifth class interval is $32-36$. The lower class limit for this interval is 32.

Step 2: Calculate the Lower Class Boundary

To find the lower class boundary, subtract 0.5 from the lower class limit: \[ \text{Lower Class Boundary} = 32 - 0.5 = 31.5 \]