Questions: Predict the products for the following precipitation reaction: NiCl2(aq) + (NH4)2 S(aq) -> NiS(aq) + 2 NH4 Cl(aq) NiS(s) + 2 NH4 Cl(aq) NiS(s) + 2 NH4 Cl(s) NiS(s) + NH4 Cl(aq)

Predict the products for the following precipitation reaction:
NiCl2(aq) + (NH4)2 S(aq) ->

NiS(aq) + 2 NH4 Cl(aq)
NiS(s) + 2 NH4 Cl(aq)
NiS(s) + 2 NH4 Cl(s)
NiS(s) + NH4 Cl(aq)

Transcript text: Predict the products for the following precipitation reaction: \[ \mathrm{NiCl}_{2}(\mathrm{aq})+\left(\mathrm{NH}_{4}\right)_{2} \mathrm{~S}(\mathrm{aq}) \rightarrow \] View Available Hint(s) $\mathrm{NiS}(\mathrm{aq})+2 \mathrm{NH}_{4} \mathrm{Cl}(\mathrm{aq})$ $\mathrm{NiS}(\mathrm{s})+2 \mathrm{NH}_{4} \mathrm{Cl}(\mathrm{aq})$ $\mathrm{NiS}(\mathrm{s})+2 \mathrm{NH}_{4} \mathrm{Cl}(\mathrm{s})$ $\mathrm{NiS}(\mathrm{s})+\mathrm{NH}_{4} \mathrm{Cl}(\mathrm{aq})$

Solution

Solution Steps

Step 1: Identify the reactants and their states

The reactants are $\mathrm{NiCl}_{2}(\mathrm{aq})$ and $(\mathrm{NH}_{4})_{2} \mathrm{S}(\mathrm{aq})$.

Step 2: Determine the possible products

The possible products are formed by exchanging the ions of the reactants:
- $\mathrm{Ni}^{2+}$ from $\mathrm{NiCl}_{2}$ and $\mathrm{S}^{2-}$ from $(\mathrm{NH}_{4})_{2} \mathrm{S}$ form $\mathrm{NiS}$.
- $\mathrm{NH}_{4}^{+}$ from $(\mathrm{NH}_{4})_{2} \mathrm{S}$ and $\mathrm{Cl}^{-}$ from $\mathrm{NiCl}_{2}$ form $\mathrm{NH}_{4} \mathrm{Cl}$.

Step 3: Determine the states of the products

$\mathrm{NiS}$ is a solid precipitate (insoluble in water).
$\mathrm{NH}_{4} \mathrm{Cl}$ is soluble in water and remains in aqueous form.

Step 4: Write the balanced chemical equation

The balanced chemical equation is: \[ \mathrm{NiCl}_{2}(\mathrm{aq}) + (\mathrm{NH}_{4})_{2} \mathrm{S}(\mathrm{aq}) \rightarrow \mathrm{NiS}(\mathrm{s}) + 2 \mathrm{NH}_{4} \mathrm{Cl}(\mathrm{aq}) \]

Step 5: Select the correct product from the given options