Transcript text: Solve.
\[
\begin{array}{l}
(x-3)(x+6)=10 x \\
x=\square
\end{array}
\]
(Simplify your answer. Type each solution
Solution
Solution Steps
To solve the equation \((x-3)(x+6)=10x\), we first expand the left-hand side and then bring all terms to one side of the equation to form a quadratic equation. Next, we solve the quadratic equation using the quadratic formula or by factoring, if possible.
Step 1: Expand the Equation
We start with the equation:
\[
(x - 3)(x + 6) = 10x
\]
Expanding the left-hand side gives:
\[
x^2 + 6x - 3x - 18 = 10x
\]
which simplifies to:
\[
x^2 + 3x - 18 = 10x
\]
Step 2: Rearrange the Equation
Next, we rearrange the equation by moving all terms to one side:
\[
x^2 + 3x - 10x - 18 = 0
\]
This simplifies to:
\[
x^2 - 7x - 18 = 0
\]
Step 3: Solve the Quadratic Equation
We can solve the quadratic equation \(x^2 - 7x - 18 = 0\) using the quadratic formula:
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
where \(a = 1\), \(b = -7\), and \(c = -18\). This yields the solutions:
\[
x = -2 \quad \text{and} \quad x = 9
\]
Final Answer
The solutions to the equation are:
\[
\boxed{x = -2} \quad \text{and} \quad \boxed{x = 9}
\]