Questions: As the block slides down the ramp, what happens to its kinetic energy K, potential energy U, and total mechanic
K decreases; U increases; E stays the same
K decreases; U increases; E increases
K increases; U increases; E increases
K increases; U decreases; E stays the same
Using conservation of energy, find the speed vb of the block at the bottom of the ramp. Express your answer in terms of some or all the variables m, v, and h and any appropriate constants.
Transcript text: As the block slides down the ramp, what happens to its kinetic energy $K$, potential energy $U$, and total mechanic
$K$ decreases; $U$ increases; $E$ stays the same
$K$ decreases; $U$ increases; $E$ increases
$K$ increases; $U$ increases; $E$ increases
$K$ increases; $U$ decreases; $E$ stays the same
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Part G
Using conservation of energy, find the speed $v_{\mathrm{b}}$ of the block at the bottom of the ramp.
Express your answer in terms of some or all the variables $m, v$, and $h$ and any appropriate constants.
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Hint 1. How to approach the problem
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Solution
Solution Steps
Step 1: Identify the Given Information
We need to find the speed \( v_b \) of the block at the bottom of the ramp using conservation of energy. The variables involved are mass \( m \), gravitational acceleration \( g \), height \( h \), and initial speed \( v_i \).
Step 2: Apply Conservation of Energy Principle
The total mechanical energy at the top of the ramp (potential energy + kinetic energy) should equal the total mechanical energy at the bottom of the ramp (kinetic energy).
Step 3: Write the Energy Equations
At the top of the ramp:
\[ E_{\text{top}} = U_{\text{top}} + K_{\text{top}} = mgh + \frac{1}{2}mv_i^2 \]
At the bottom of the ramp:
\[ E_{\text{bottom}} = K_{\text{bottom}} = \frac{1}{2}mv_b^2 \]
Step 4: Set Up the Conservation of Energy Equation
Since energy is conserved:
\[ mgh + \frac{1}{2}mv_i^2 = \frac{1}{2}mv_b^2 \]