Questions: Solve -6+4 * 2^x=30. A. x=log 2(9) B. x=log 8(9) C. x=log 4(18) D. x=log 9(2)

Solve -6+4 * 2^x=30.
A. x=log 2(9)
B. x=log 8(9)
C. x=log 4(18)
D. x=log 9(2)
Transcript text: Solve $-6+4 \cdot 2^{x}=30$. A. $x=\log _{2}(9)$ B. $x=\log _{8}(9)$ C. $x=\log _{4}(18)$ D. $x=\log _{9}(2)$
failed

Solution

failed
failed

Solution Steps

Step 1: Isolate the Exponential Term

Starting with the equation: \[ -6 + 4 \cdot 2^x = 30 \] we add 6 to both sides: \[ 4 \cdot 2^x = 36 \]

Step 2: Simplify the Equation

Next, we divide both sides by 4: \[ 2^x = 9 \]

Step 3: Solve for \(x\)

To find \(x\), we take the logarithm base 2 of both sides: \[ x = \log_2(9) \] Calculating this gives: \[ x \approx 3.1699 \]

Final Answer

The solution to the equation is \[ \boxed{x \approx 3.1699} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful