The vector v is found by subtracting the initial point from the terminal point: (8-(-7), 15-5) = (15, 10)
The direction angle θ of vector v = <x,y> is given by tan θ = y/x.
In this case, tan θ = 10/15 = 2/3. θ = arctan(2/3) ≈ 33.69°
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