Solve for the time when the temperature of the ginger ale is \(51^{\circ} \mathrm{F}\).
Set up the equation using the temperature model.
We are given the temperature model \( T = 36 + 39e^{-0.0405t} \) and we want to find the time \( t \) when the temperature \( T \) is \( 51^{\circ} \mathrm{F} \). Set up the equation:
\[ 51 = 36 + 39e^{-0.0405t} \]
Isolate the exponential term.
Subtract 36 from both sides of the equation:
\[ 15 = 39e^{-0.0405t} \]
Solve for the exponential term.
Divide both sides by 39:
\[ \frac{15}{39} = e^{-0.0405t} \]
Take the natural logarithm of both sides.
Apply the natural logarithm to both sides:
\[ \ln\left(\frac{15}{39}\right) = -0.0405t \]
Solve for \( t \).
Divide by \(-0.0405\) to solve for \( t \):
\[ t = \frac{\ln\left(\frac{15}{39}\right)}{-0.0405} \]
Using a calculator, we find:
\[ t \approx 24 \]
The temperature of the ginger ale will be \( 51^{\circ} \mathrm{F} \) after approximately \(\boxed{24}\) minutes.
The temperature of the ginger ale will be \( 51^{\circ} \mathrm{F} \) after approximately \(\boxed{24}\) minutes.