Questions: Solve the inequality. Give the answer in interval notation. 6+3x ≤ 12 Interval notation for the answer is

Solution Steps

To solve the inequality \(6 + 3x \leq 12\), we need to isolate the variable \(x\). First, subtract 6 from both sides of the inequality, then divide both sides by 3. Finally, express the solution in interval notation.

First, we need to isolate the term containing the variable \( x \). We start by subtracting 6 from both sides of the inequality: \[ 6 + 3x \leq 12 \] \[ 6 + 3x - 6 \leq 12 - 6 \] \[ 3x \leq 6 \]

Next, we divide both sides of the inequality by 3 to solve for \( x \): \[ \frac{3x}{3} \leq \frac{6}{3} \] \[ x \leq 2 \]

The solution to the inequality \( x \leq 2 \) in interval notation is: \[ (-\infty, 2] \]

Final Answer