Questions: The standard length of a football field is 4,320 inches long. You measure your local football field and it measures at 4,225 inches. What is the percent error? % Error = (accepted -average / accepted) x 100

The standard length of a football field is 4,320 inches long. You measure your local football field and it measures at 4,225 inches. What is the percent error?

% Error = (accepted -average / accepted) x 100
Transcript text: The standard length of a football field 4,320 inches long. You measure your local football field and it measures at 4,225 inches. What is the percent error? \[ \% \text { Error }=\frac{\text { laccepted -averagel }}{\text { accepted }} \times 100 \]
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Solution

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Solution Steps

Step 1: Identify the Accepted and Measured Values

The accepted length of the football field is 4,320 inches, and the measured length is 4,225 inches.

Step 2: Calculate the Absolute Difference

Calculate the absolute difference between the accepted and measured values: acceptedmeasured=43204225=95 |\text{accepted} - \text{measured}| = |4320 - 4225| = 95

Step 3: Calculate the Percent Error

Use the percent error formula: % Error=acceptedmeasuredaccepted×100 \% \text{ Error} = \frac{|\text{accepted} - \text{measured}|}{\text{accepted}} \times 100 Substitute the values: % Error=954320×1002.1991 \% \text{ Error} = \frac{95}{4320} \times 100 \approx 2.1991

Final Answer

The percent error is approximately 2.2 percent error\boxed{2.2 \text{ percent error}}.

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