Questions: A student weighs out 20.93 grams of sodium permanganate, NaMnO4. How many moles of NaMnO4 is this? The molar mass of NaMnO4 is 141.93 g / mol. Use the standard abbreviation for the units.

A student weighs out 20.93 grams of sodium permanganate, NaMnO4. How many moles of NaMnO4 is this? The molar mass of NaMnO4 is 141.93 g / mol. Use the standard abbreviation for the units.
Transcript text: A student weighs out 20.93 grams of sodium permanganate, $\mathrm{NaMnO}_{4}$. How many moles of $\mathrm{NaMnO}_{4}$ is this? The molar mass of $\mathrm{NaMnO}_{4}$ is $141.93 \mathrm{~g} / \mathrm{mol}$. Use the standard abbreviation for the units. Your Answer: $\square$ Answer $\square$ units
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Solution

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Solution Steps

Step 1: Identify the given values

We are given:

  • Mass of sodium permanganate, $\mathrm{NaMnO}_{4}$: 20.93 grams
  • Molar mass of $\mathrm{NaMnO}_{4}$: 141.93 g/mol
Step 2: Use the formula to calculate moles

The formula to calculate the number of moles is: \[ \text{moles} = \frac{\text{mass}}{\text{molar mass}} \]

Step 3: Substitute the given values into the formula

\[ \text{moles} = \frac{20.93 \, \text{g}}{141.93 \, \text{g/mol}} \]

Step 4: Perform the calculation

\[ \text{moles} = \frac{20.93}{141.93} \approx 0.1475 \, \text{mol} \]

Final Answer

\[ \boxed{0.1475 \, \text{mol}} \]

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