The results of the analysis are as follows:
- Probability of exactly 3 successes: \( P(X = 3) = 0.1911 \)
- Mean (expected value): \( \mu = 1.8 \)
- Variance: \( \sigma^2 = 1.152 \)
- Standard Deviation: \( \sigma = 1.0733 \)
Thus, the final boxed answer is:
\[
\boxed{P(X = 3) = 0.1911, \mu = 1.8, \sigma^2 = 1.152, \sigma = 1.0733}
\]