Questions: How many moles of sulfate ions are contained in 250 grams of aluminum sulfate? There are 0.731 moles of sulfate ions in 250 grams of aluminum sulfate There are 2.19 moles of sulfate ions in 250 grams of aluminum sulfate. There are 1.46 moles of sulfate ions in 250 grams of aluminum sulfate. There are 2.92 moles of sulfate ions in 250 grams of aluminum sulfate.

How many moles of sulfate ions are contained in 250 grams of aluminum sulfate? There are 0.731 moles of sulfate ions in 250 grams of aluminum sulfate There are 2.19 moles of sulfate ions in 250 grams of aluminum sulfate. There are 1.46 moles of sulfate ions in 250 grams of aluminum sulfate. There are 2.92 moles of sulfate ions in 250 grams of aluminum sulfate.
Transcript text: How many moles of sulfate ions are contained in 250 grams of aluminum sulfate? There are 0.731 moles of sulfate ions in 250 grams of aluminum sulfate There are 2.19 moles of sulfate ions in 250 grams of aluminum sulfate. There are 1.46 moles of sulfate ions in 250 grams of aluminum sulfate. There are 2.92 moles of sulfate ions in 250 grams of aluminum sulfate.
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Solution

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Solution Steps

Step 1: Determine the molar mass of aluminum sulfate

The chemical formula for aluminum sulfate is \( \text{Al}_2(\text{SO}_4)_3 \).

To find the molar mass, we sum the atomic masses of all atoms in the formula:

  • Aluminum (Al): \( 2 \times 26.98 \, \text{g/mol} = 53.96 \, \text{g/mol} \)
  • Sulfur (S): \( 3 \times 32.07 \, \text{g/mol} = 96.21 \, \text{g/mol} \)
  • Oxygen (O): \( 12 \times 16.00 \, \text{g/mol} = 192.00 \, \text{g/mol} \)

Total molar mass of \( \text{Al}_2(\text{SO}_4)_3 \): \[ 53.96 + 96.21 + 192.00 = 342.17 \, \text{g/mol} \]

Step 2: Calculate the moles of aluminum sulfate in 250 grams

Using the molar mass, we can find the number of moles of aluminum sulfate in 250 grams: \[ \text{moles of } \text{Al}_2(\text{SO}_4)_3 = \frac{250 \, \text{g}}{342.17 \, \text{g/mol}} = 0.7305 \, \text{moles} \]

Step 3: Determine the moles of sulfate ions

Each formula unit of aluminum sulfate contains 3 sulfate ions (\(\text{SO}_4^{2-}\)).

Therefore, the moles of sulfate ions are: \[ \text{moles of } \text{SO}_4^{2-} = 0.7305 \, \text{moles of } \text{Al}_2(\text{SO}_4)_3 \times 3 = 2.1915 \, \text{moles} \]

Final Answer

\(\boxed{2.19 \text{ moles of sulfate ions}}\)

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