The given equation is:
\[ PH(x) = 6.1 + \log \left(\frac{800}{x}\right) \]
We need to find the value of \(x\) (partial pressure) when \(PH(x) = 7.5\).
Substitute \(PH(x) = 7.5\) into the equation:
\[ 7.5 = 6.1 + \log \left(\frac{800}{x}\right) \]
Subtract 6.1 from both sides to isolate the logarithmic term:
\[ 7.5 - 6.1 = \log \left(\frac{800}{x}\right) \]
\[ 1.4 = \log \left(\frac{800}{x}\right) \]
To solve for \(x\), rewrite the equation in exponential form:
\[ 10^{1.4} = \frac{800}{x} \]
Calculate \(10^{1.4}\):
\[ 10^{1.4} \approx 25.1189 \]
Now solve for \(x\):
\[ x = \frac{800}{25.1189} \]
\[ x \approx 31.8450 \]
The partial pressure \(x\) when \(PH(x) = 7.5\) is approximately:
\[ \boxed{x \approx 31.8450} \]
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