Questions: Next, the chemist measures the volume of the unknown liquid as 0.577 L and the mass of the unknown liquid as 728 g.
Calculate the density of the liquid. Be sure your answer has the correct number of significant digits. g . cm^-3
Given the data above, is it possible to identify the liquid? yes no
tetrahydrofuran acetone dimethyl sulfoxide glycerol pentane
Transcript text: Next, the chemist measures the volume of the unknown liquid as 0.577 L and the mass of the unknown liquid as $728 . \mathrm{g}$.
\begin{tabular}{|l|l|}
\hline \begin{tabular}{l}
Calculate the density of the liquid. Be sure \\
your answer has the correct number of \\
significant digits.
\end{tabular} & \begin{tabular}{l}
$\mathrm{g} \cdot \mathrm{cm}^{-3}$
\end{tabular} \\
\hline \begin{tabular}{l}
Given the data above, is it possible to \\
identify the liquid?
\end{tabular} & \begin{tabular}{l}
yes \\
no
\end{tabular} \\
\hline & \begin{tabular}{l}
tetrahydrofuran \\
acetone \\
dimethyl sulfoxide \\
glycerol \\
pentane
\end{tabular} \\
\hline
\end{tabular}
Solution
Solution Steps
Step 1: Calculate the Density of the Unknown Liquid
To calculate the density of the unknown liquid, we use the formula:
$$\text{Density} = \frac{\text{Mass}}{\text{Volume}}$$
Given that the mass of the unknown liquid is 728 g and the volume is 577 cm^3,
the calculated density is 1.262 g/cm^3 after rounding to 3 decimal places.
Step 2: Compare the Calculated Density with Known Densities
We compare the calculated density with the known densities of possible liquids.
The calculated density closely matches the density of glycerol, with a difference of 0.001 g/cm^3.
Final Answer:
The unknown liquid is likely glycerol, based on its density.