Questions: Find the vertical asymptotes, if any, and the values of x corresponding to holes, if any, of the graph of the rational function.
f(x) = (x-3)/(x^2-9x+18)
Transcript text: Find the vertical asymptoles, if any, and the values of $x$ corresponding to holes, if any, of the graph of the rational function.
\[
f(x)=\frac{x-3}{x^{2}-9 x+18}
\]
Solution
Solution Steps
Step 1: Factor the Denominator
The given rational function is
\[
f(x) = \frac{x - 3}{x^2 - 9x + 18}
\]
First, we factor the denominator:
\[
x^2 - 9x + 18 = (x - 6)(x - 3)
\]
Step 2: Find the Roots of the Denominator
The roots of the denominator are found by setting each factor equal to zero:
\[
x - 6 = 0 \quad \Rightarrow \quad x = 6
\]
\[
x - 3 = 0 \quad \Rightarrow \quad x = 3
\]
Step 3: Determine Vertical Asymptotes and Holes
To determine whether these roots correspond to vertical asymptotes or holes, we check the numerator at these points:
For \(x = 3\), the numerator is \(x - 3 = 0\). Since both the numerator and denominator are zero, there is a hole at \(x = 3\).
For \(x = 6\), the numerator is \(x - 3 = 3\). Since the numerator is not zero, there is a vertical asymptote at \(x = 6\).
Final Answer
The vertical asymptote is at \(x = 6\) and there is a hole at \(x = 3\).
\[
\boxed{\text{Vertical Asymptote: } x = 6}
\]
\[
\boxed{\text{Hole: } x = 3}
\]