Questions: A sample of argon gas has a volume of 4.50 L at a pressure of 4.00 atm. The temperature and the number of gas particles do not change. Note: Reference the Conversion factors for non-SI units table for additional information. What is the volume of gas (in L) at 22.8 atm? Be sure your answer has the correct number of significant figures. L × 10

Solution Steps

We are given:

• Initial volume, \( V_1 = 4.50 \) L
• Initial pressure, \( P_1 = 4.00 \) atm
• Final pressure, \( P_2 = 22.8 \) atm

We need to find the final volume, \( V_2 \).

Boyle's Law states that for a given mass of gas at constant temperature, the product of pressure and volume is constant: \[ P_1 V_1 = P_2 V_2 \]

Rearrange the equation to solve for \( V_2 \): \[ V_2 = \frac{P_1 V_1}{P_2} \]

Substitute the given values into the equation: \[ V_2 = \frac{4.00 \, \text{atm} \times 4.50 \, \text{L}}{22.8 \, \text{atm}} \]

Perform the calculation: \[ V_2 = \frac{18.00 \, \text{L} \cdot \text{atm}}{22.8 \, \text{atm}} \approx 0.7895 \, \text{L} \]

Final Answer