Questions: Find the local minimum and maximum values of f. f(x)=x^top ln(x)
Transcript text: Find the local minimum and maximum values of $f$.
\[
f(x)=x^{\top} \ln (x)
\]
Solution
Solution Steps
To find the local minimum and maximum values of the function \( f(x) = x^{\top} \ln(x) \), we need to follow these steps:
Compute the first derivative of the function \( f(x) \).
Set the first derivative equal to zero to find the critical points.
Compute the second derivative of the function \( f(x) \).
Use the second derivative test to determine whether each critical point is a local minimum, local maximum, or neither.
Step 1: Define the Function
We start with the function defined as:
\[
f(x) = x \ln(x)
\]
Step 2: Compute the First Derivative
The first derivative of the function is calculated as:
\[
f'(x) = \ln(x) + 1
\]
Step 3: Find Critical Points
To find the critical points, we set the first derivative equal to zero:
\[
\ln(x) + 1 = 0 \implies \ln(x) = -1 \implies x = e^{-1}
\]
Thus, the critical point is:
\[
x = e^{-1}
\]
Step 4: Compute the Second Derivative
The second derivative of the function is:
\[
f''(x) = \frac{1}{x}
\]
Step 5: Determine the Nature of the Critical Point
We evaluate the second derivative at the critical point \( x = e^{-1} \):
\[
f''(e^{-1}) = \frac{1}{e^{-1}} = e
\]
Since \( f''(e^{-1}) > 0 \), this indicates that \( x = e^{-1} \) is a local minimum.
Final Answer
The local minimum occurs at:
\[
\boxed{x = e^{-1}}
\]