Questions: Determine whether (y^2=2 x^2-1) is a function.
Select the correct answer below:
yes
no
Transcript text: Determine whether $y^{2}=2 x^{2}-1$ is a function.
Select the correct answer below:
yes
no
Solution
Solution Steps
To determine if \( y^2 = 2x^2 - 1 \) is a function, we need to check if for every value of \( x \), there is exactly one corresponding value of \( y \). If there are multiple values of \( y \) for a single \( x \), then it is not a function.
Solution Approach
Rearrange the equation to solve for \( y \).
Check if the resulting expression for \( y \) gives a unique value for each \( x \).
Step 1: Rearrange the Equation
We start with the equation:
\[ y^2 = 2x^2 - 1 \]
Step 2: Solve for \( y \)
To determine if this relation is a function, we solve for \( y \):
\[ y = \pm \sqrt{2x^2 - 1} \]
Step 3: Analyze the Solutions
The solutions are:
\[ y = \sqrt{2x^2 - 1} \]
\[ y = -\sqrt{2x^2 - 1} \]
For each value of \( x \), there are two possible values of \( y \) (one positive and one negative), except when \( 2x^2 - 1 = 0 \). This means that for most values of \( x \), there are two corresponding values of \( y \).
Final Answer
Since there are multiple values of \( y \) for a single value of \( x \), the relation \( y^2 = 2x^2 - 1 \) is not a function.