Given the equation \(2x - 3y = 6\), we need to find the value of \(x\) when \(y = -4\).
\[ 2x - 3(-4) = 6 \]
\[ 2x + 12 = 6 \]
\[ 2x = 6 - 12 \]
\[ 2x = -6 \]
\[ x = -3 \]
The completed table is:
\[ \begin{array}{|c|c|} \hline x & y \\ \hline 0 & -2 \\ \hline 3 & 0 \\ \hline 6 & 2 \\ \hline -3 & -4 \\ \hline \end{array} \]
The missing value in the table is \(x = -3\).
{"axisType": 3, "coordSystem": {"xmin": -5, "xmax": 7, "ymin": -5, "ymax": 5}, "commands": ["y = (2/3)x - 2"], "latex_expressions": ["$2x - 3y = 6$"]}
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