Let the third angle be \(y\).
The sum of the angles in a triangle is \(180^\circ\).
Therefore, \(60^\circ + 78^\circ + y = 180^\circ\).
\(138^\circ + y = 180^\circ\)
\(y = 180^\circ - 138^\circ\)
\(y = 42^\circ\)
The third angle of the triangle is \(42^\circ\).
Find the value of \(x\).
\(x\) and \(y\) are supplementary angles, so their sum is \(180^\circ\).
\(x + y = 180^\circ\)
\(x + 42^\circ = 180^\circ\)
\(x = 180^\circ - 42^\circ\)
\(x = 138^\circ\)