Questions: Consider the given function p(x)=2x^2-8x-1 (a) Write the function in vertex form. (b) Identify the vertex. (c) Determine the x-intercept(s). (d) Determine the y-intercept(s).

Consider the given function p(x)=2x^2-8x-1
(a) Write the function in vertex form.
(b) Identify the vertex.
(c) Determine the x-intercept(s).
(d) Determine the y-intercept(s).
Transcript text: Consider the given function $p(x)=2 x^{2}-8 x-1$ (a) Write the function in vertex form. (b) Identify the vertex. (c) Determine the $x$-intercept(s). (d) Determine the $y$-intercept(s).
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Solution

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Solution Steps

Solution Approach

(a) To write the quadratic function in vertex form, we can complete the square. This involves rearranging the quadratic expression into a perfect square trinomial plus a constant.

(b) Once the function is in vertex form, the vertex can be directly identified from the expression as it will be in the form \( a(x-h)^2 + k \), where \((h, k)\) is the vertex.

(c) To find the \(x\)-intercepts, set the function equal to zero and solve for \(x\). This can be done using the quadratic formula or by factoring if possible.

Step 1: Convert the Function to Vertex Form

The given function is \( p(x) = 2x^2 - 8x - 1 \). To convert this quadratic function into vertex form, we need to complete the square.

  1. Factor out the coefficient of \( x^2 \) from the first two terms: \[ p(x) = 2(x^2 - 4x) - 1 \]

  2. Complete the square inside the parentheses:

    • Take half of the coefficient of \( x \), square it, and add and subtract it inside the parentheses.
    • The coefficient of \( x \) is \(-4\). Half of \(-4\) is \(-2\), and \((-2)^2 = 4\).
  3. Add and subtract 4 inside the parentheses: \[ p(x) = 2(x^2 - 4x + 4 - 4) - 1 \]

  4. Simplify by completing the square: \[ p(x) = 2((x - 2)^2 - 4) - 1 \]

  5. Distribute the 2 and simplify: \[ p(x) = 2(x - 2)^2 - 8 - 1 = 2(x - 2)^2 - 9 \]

Thus, the vertex form of the function is: \[ p(x) = 2(x - 2)^2 - 9 \]

Step 2: Identify the Vertex

The vertex form of a quadratic function is \( a(x - h)^2 + k \), where \((h, k)\) is the vertex.

From the vertex form \( p(x) = 2(x - 2)^2 - 9 \), we can see that:

  • \( h = 2 \)
  • \( k = -9 \)

Therefore, the vertex is \((2, -9)\).

Step 3: Determine the \(x\)-Intercept(s)

To find the \(x\)-intercepts, set \( p(x) = 0 \) and solve for \( x \): \[ 2(x - 2)^2 - 9 = 0 \]

  1. Add 9 to both sides: \[ 2(x - 2)^2 = 9 \]

  2. Divide by 2: \[ (x - 2)^2 = \frac{9}{2} \]

  3. Take the square root of both sides: \[ x - 2 = \pm \sqrt{\frac{9}{2}} \]

  4. Solve for \( x \): \[ x = 2 \pm \sqrt{\frac{9}{2}} \]

  5. Simplify: \[ x = 2 \pm \frac{3\sqrt{2}}{2} \]

Thus, the \(x\)-intercepts are: \[ x = 2 + \frac{3\sqrt{2}}{2} \quad \text{and} \quad x = 2 - \frac{3\sqrt{2}}{2} \]

Final Answer

  • (a) Vertex form: \(\boxed{p(x) = 2(x - 2)^2 - 9}\)
  • (b) Vertex: \(\boxed{(2, -9)}\)
  • (c) \(x\)-Intercepts: \(\boxed{x = 2 \pm \frac{3\sqrt{2}}{2}}\)
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