Questions: Exercise 7.7 Solve. 3x + 2y = 6 6x + 4y = 16

Exercise 7.7 Solve.
3x + 2y = 6
6x + 4y = 16
Transcript text: Exercise 7.7 Solve. \[ \begin{array}{l} 3 x+2 y=6 \\ 6 x+4 y=16 \end{array} \]
failed

Solution

failed
failed

Solution Steps

To solve the system of linear equations, we can use matrix operations or a solver function from a library like NumPy. The equations can be represented in matrix form \(AX = B\), where \(A\) is the coefficient matrix, \(X\) is the variable matrix, and \(B\) is the constant matrix. We can then use NumPy's linalg.solve function to find the values of \(x\) and \(y\).

Step 1: Write the System of Equations

We start with the given system of linear equations: \[ \begin{array}{l} 3x + 2y = 6 \\ 6x + 4y = 16 \end{array} \]

Step 2: Simplify the Second Equation

Notice that the second equation can be simplified by dividing every term by 2: \[ 6x + 4y = 16 \implies 3x + 2y = 8 \]

Step 3: Compare the Equations

Now we have the simplified system: \[ \begin{array}{l} 3x + 2y = 6 \\ 3x + 2y = 8 \end{array} \]

Step 4: Analyze the System

We observe that the two equations are: \[ 3x + 2y = 6 \quad \text{and} \quad 3x + 2y = 8 \] These two equations are contradictory because the same linear combination of \(x\) and \(y\) cannot equal two different constants (6 and 8).

Final Answer

Since the system of equations is inconsistent, there is no solution.

\[ \boxed{\text{No solution}} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful