Questions: Assume the random variable X is normally distributed with mean μ=50 and standard deviation σ=7. Compute the probability. Be sure to draw a normal curve with the area corresponding to the probability shaded.
1 of
P(X>38)
Click the icon to view a table of areas under the normal curve.
Which of the following normal curves corresponds to P(X>38) ?
A.
B.
c.
P(X>38)=
(Round to four decimal places as needed.)
Transcript text: Assume the random variable $X$ is normally distributed with mean $\mu=50$ and standard deviation $\sigma=7$. Compute the probability. Be sure to draw a normal curve with the area corresponding to the probability shaded.
1 of
\[
P(X>38)
\]
Click the icon to view a table of areas under the normal curve.
Which of the following normal curves corresponds to $P(X>38)$ ?
A.
B.
c.
\[
P(X>38)=
\]
$\square$
(Round to four decimal places as needed.)
Solution
Solution Steps
Step 1: Identify the given parameters
The problem states that the random variable \( X \) is normally distributed with a mean \( \mu = 50 \) and a standard deviation \( \sigma = 7 \). We need to compute the probability \( P(X > 38) \).
Step 2: Standardize the variable
To find \( P(X > 38) \), we first convert the value 38 to a z-score using the formula:
\[ z = \frac{X - \mu}{\sigma} \]
Substituting the given values:
\[ z = \frac{38 - 50}{7} = \frac{-12}{7} \approx -1.7143 \]
Step 3: Use the z-score to find the probability
We need to find the probability that \( Z \) (the standard normal variable) is greater than -1.7143. Using the standard normal distribution table or a calculator, we find the cumulative probability up to \( z = -1.7143 \).
The cumulative probability for \( z = -1.7143 \) is approximately 0.0432. Since we want \( P(Z > -1.7143) \):
\[ P(Z > -1.7143) = 1 - P(Z \leq -1.7143) = 1 - 0.0432 = 0.9568 \]
Step 4: Identify the correct normal curve
The correct normal curve corresponding to \( P(X > 38) \) is the one where the area to the right of 38 is shaded. This corresponds to option C.