Questions: aqueous solutions of hydrobromic acid and strontium hydroxide are mixed together. Balance the molecular equation, what is the coefficients for the hydrobromic acid? fill in blank

aqueous solutions of hydrobromic acid and strontium hydroxide are mixed together. Balance the molecular equation, what is the coefficients for the hydrobromic acid? fill in blank
Transcript text: aqueous solutions of hydrobromic acid and strontium hydroxide are mixed together. Balance the molecular equation, what is the coefficients for the hydrobromic acid? fill in blank
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Solution

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Solution Steps

Step 1: Write the unbalanced molecular equation

First, we write the unbalanced molecular equation for the reaction between hydrobromic acid (HBr) and strontium hydroxide (Sr(OH)₂):

\[ \text{HBr} + \text{Sr(OH)}_2 \rightarrow \text{SrBr}_2 + \text{H}_2\text{O} \]

Step 2: Identify the number of atoms of each element

Next, we count the number of atoms of each element on both sides of the equation:

  • Reactants:

    • H: 1 (from HBr) + 2 (from Sr(OH)₂) = 3
    • Br: 1 (from HBr)
    • Sr: 1 (from Sr(OH)₂)
    • O: 2 (from Sr(OH)₂)

  • Products:

    • H: 2 (from H₂O)
    • Br: 2 (from SrBr₂)
    • Sr: 1 (from SrBr₂)
    • O: 1 (from H₂O)
Step 3: Balance the equation

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides. We start by balancing the bromine (Br) atoms:

\[ 2 \text{HBr} + \text{Sr(OH)}_2 \rightarrow \text{SrBr}_2 + \text{H}_2\text{O} \]

Now, we count the atoms again:

  • Reactants:

    • H: 2 (from 2 HBr) + 2 (from Sr(OH)₂) = 4
    • Br: 2 (from 2 HBr)
    • Sr: 1 (from Sr(OH)₂)
    • O: 2 (from Sr(OH)₂)

  • Products:

    • H: 2 (from H₂O)
    • Br: 2 (from SrBr₂)
    • Sr: 1 (from SrBr₂)
    • O: 1 (from H₂O)

Next, we balance the hydrogen (H) atoms by adjusting the coefficient of water (H₂O):

\[ 2 \text{HBr} + \text{Sr(OH)}_2 \rightarrow \text{SrBr}_2 + 2 \text{H}_2\text{O} \]

Now, we count the atoms again:

  • Reactants:

    • H: 2 (from 2 HBr) + 2 (from Sr(OH)₂) = 4
    • Br: 2 (from 2 HBr)
    • Sr: 1 (from Sr(OH)₂)
    • O: 2 (from Sr(OH)₂)

  • Products:

    • H: 4 (from 2 H₂O)
    • Br: 2 (from SrBr₂)
    • Sr: 1 (from SrBr₂)
    • O: 2 (from 2 H₂O)

Now, the equation is balanced.

Final Answer

The coefficient for hydrobromic acid (HBr) is \(\boxed{2}\).

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