Questions: If f(x) = x^3 - 1, g(x) = x - 6, and h(x) = sqrt(x), find the following:
a) f(g(h(x)))
Transcript text: If $f(x)=x^{3}-1, g(x)=x-6$, and $h(x)=\sqrt{x}$, find the following:
a) $f(g(h(x)))$
Solution
Solution Steps
To solve the problem, we need to find the composition of the functions \( f \), \( g \), and \( h \). Specifically, we need to evaluate \( f(g(h(x))) \). This involves the following steps:
Compute \( h(x) \).
Substitute \( h(x) \) into \( g(x) \) to get \( g(h(x)) \).
Substitute \( g(h(x)) \) into \( f(x) \) to get \( f(g(h(x))) \).
Step 1: Compute \( h(x) \)
Given \( h(x) = \sqrt{x} \), we start by evaluating \( h(x) \).
Step 2: Substitute \( h(x) \) into \( g(x) \)
Next, we substitute \( h(x) \) into \( g(x) \). Given \( g(x) = x - 6 \), we have:
\[ g(h(x)) = g(\sqrt{x}) = \sqrt{x} - 6 \]
Step 3: Substitute \( g(h(x)) \) into \( f(x) \)
Finally, we substitute \( g(h(x)) \) into \( f(x) \). Given \( f(x) = x^3 - 1 \), we have:
\[ f(g(h(x))) = f(\sqrt{x} - 6) = (\sqrt{x} - 6)^3 - 1 \]