Calculate \( A_x \) and \( A_y \):
- \( A_x = 8 \cos(25°) \approx 7.25 \)
- \( A_y = -8 \sin(25°) \approx -3.38 \)
Calculate \( B_x \) and \( B_y \):
- \( B_x = 10 \cos(30°) \approx 8.66 \)
- \( B_y = 10 \sin(30°) \approx 5.00 \)
Sum the components:
- \( R_x = 7.25 + 8.66 \approx 15.91 \)
- \( R_y = -3.38 + 5.00 \approx 1.62 \)
Calculate the magnitude and direction:
- \( R = \sqrt{15.91^2 + 1.62^2} \approx 16.00 \)
- \( \theta = \tan^{-1}\left(\frac{1.62}{15.91}\right) \approx 5.82° \) above the x-axis
The resultant vector \( \mathbf{R} \) has a magnitude of approximately 16.00 m and is directed at an angle of approximately 5.82° above the x-axis.