Questions: The gas mileages (in miles per gallon) of 23 randomly selected sports cans are listed in the accompanying table. Assume the mileages are not normally distributed. Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. Let σ be the population standard deviation and let n be the sample size. Which distribution should be used to construct the confidence interval? A t-distribution should be used to construct the confidence interval, since - σ is unknown. - the population is not normally distributed and n ≥ 10. - σ is known and the population is not normally distributed. - σ is known and n<30. - σ is known and n ≥ 10. - σ is unknown and n<30. - σ is unknown and the population is not normally distributed. - the population is not normally distributed and n<30. - σ is unknown and n ≥ 10.

Transcript text: The gas mileages (in miles per gallon) of 23 randomly selected sports cans are listed in the accompanying table. Assume the mileages are not normally distributed. Use the standard normal distribution or the t-distribution to construct a $99 \%$ confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. Let $\sigma$ be the population standard deviation and let n be the sample size. Which distribution should be used to construct the confidence interval? A $t$-istribution should be used to construct the confidence interval, since - $\sigma$ is unknown. - the population is not normally distributed and $n \geq 10$. - $\sigma$ is known and the population is not normally distributed. - $\sigma$ is known and $n<30$. - $\sigma$ is known and $\mathrm{n} \geq 10$. - $\sigma$ is unknown and $n<30$. - $\sigma$ is unknown and the population is not normally distributed. - the population is not normally distributed and $n<30$. - $\sigma$ is unknown and $n \geq 10$.