Questions: Construct a frequency table for the data Responses Frequency excellent 1 good 2 fair 4 poor 3 Total 10 Construct a relative frequency table for the data. Responses Relative Frequency excellent good fair poor Total (Type integers or decimals)

Construct a frequency table for the data Responses Frequency excellent 1 good 2 fair 4 poor 3 Total 10 Construct a relative frequency table for the data. Responses Relative Frequency excellent good fair poor Total (Type integers or decimals)
Transcript text: Part 2 of 3 Points: 0 of 1 Construct a frequency table for the data \begin{tabular}{|c|c|} \hline Responses & Frequency \\ \hline excellent & 1 \\ \hline good & 2 \\ \hline fair & 4 \\ \hline poor & 3 \\ \hline Total & 10 \\ \hline \end{tabular} Construct a relative frequency table for the data. \begin{tabular}{|c|c|} \hline Responses & \begin{tabular}{c} Relative \\ Frequency \end{tabular} \\ \hline excellent & $\square$ \\ good \\ fair \\ poor & $\square$ \\ \hline Total & $\square$ \\ \hline \end{tabular} (Type integers or decimals)
failed

Solution

failed
failed

Solution Steps

To construct a relative frequency table, we need to divide the frequency of each response by the total number of responses. This will give us the relative frequency for each category.

Solution Approach
  1. Extract the frequencies of each response.
  2. Calculate the total number of responses.
  3. Divide the frequency of each response by the total number of responses to get the relative frequency.
  4. Populate the relative frequency table with these values.
Step 1: Calculate Total Responses

The total number of responses is calculated by summing the frequencies of each category: \[ \text{Total} = 1 + 2 + 4 + 3 = 10 \]

Step 2: Calculate Relative Frequencies

The relative frequency for each response category is calculated using the formula: \[ \text{Relative Frequency} = \frac{\text{Frequency}}{\text{Total Responses}} \] Thus, we have:

  • For "excellent": \[ \text{Relative Frequency}_{\text{excellent}} = \frac{1}{10} = 0.1 \]
  • For "good": \[ \text{Relative Frequency}_{\text{good}} = \frac{2}{10} = 0.2 \]
  • For "fair": \[ \text{Relative Frequency}_{\text{fair}} = \frac{4}{10} = 0.4 \]
  • For "poor": \[ \text{Relative Frequency}_{\text{poor}} = \frac{3}{10} = 0.3 \]
Step 3: Summarize Relative Frequencies

The relative frequencies for each response category are:

  • Excellent: \(0.1\)
  • Good: \(0.2\)
  • Fair: \(0.4\)
  • Poor: \(0.3\)

The total of the relative frequencies is: \[ \text{Total Relative Frequency} = 0.1 + 0.2 + 0.4 + 0.3 = 1.0 \]

Final Answer

The relative frequency table is as follows:

  • Excellent: \(0.1\)
  • Good: \(0.2\)
  • Fair: \(0.4\)
  • Poor: \(0.3\)
  • Total: \(1.0\)

Thus, the final answer is: \[ \boxed{\text{Relative Frequencies: Excellent = 0.1, Good = 0.2, Fair = 0.4, Poor = 0.3, Total = 1.0}} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful

Questions asked by other users

failedAnswered
Let g(x)=3x and h(x)=x-2. Find the following. (g+h)(1/5)
failedAnswered
Where does calcium attach to the contractile protein complex? myosin actin troponin tropomyosin
failedAnswered
2. A manufacturer can sell a certain product for 110 per unit. Total cost consists of a fixed overhead of 7,500 plus production cost of 60 per unit. (a) How many units must the manufacturer sell to break even? (b) What is the manufacturer's profit or loss if 100 units are sold? (c) How many units must be sold for the manufacturer to make a profit of 1250?
failedAnswered
Use the given formal definition to prove the limit statement. lim x -> 0^- (1/x) = -∞ The function f(x) approaches minus infinity as x approaches c from the left, written lim x -> c^- f(x) = -∞, if, for every negative real number -B there exists a corresponding number δ>0 such that for all x, c-δ<x<c -> f(x)<-B. Complete the introduction statement. Given -B<0, find δ>0 such that for all x, <x< -> 1/x<-B.
failedAnswered
Evaluate the given difference. Report the answer with the correct number of significant figures. 137.914-22.6=