Questions: (NH4)3PO4

(NH4)3PO4
Transcript text: $\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}$
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Solution

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Solution Steps

Step 1: Identify the Chemical Compound

The given chemical formula is \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\). This represents ammonium phosphate.

Step 2: Determine the Composition

The compound consists of ammonium ions \(\mathrm{NH}_{4}^+\) and phosphate ions \(\mathrm{PO}_{4}^{3-}\).

Step 3: Calculate the Molar Mass

To find the molar mass, calculate the mass of each element in the compound:

  • Nitrogen (N): \(3 \times 1 \times 14.01 = 42.03 \, \text{g/mol}\)
  • Hydrogen (H): \(3 \times 4 \times 1.008 = 12.096 \, \text{g/mol}\)
  • Phosphorus (P): \(1 \times 30.97 = 30.97 \, \text{g/mol}\)
  • Oxygen (O): \(4 \times 16.00 = 64.00 \, \text{g/mol}\)

Add these values to get the total molar mass: \[ 42.03 + 12.096 + 30.97 + 64.00 = 149.096 \, \text{g/mol} \]

Final Answer

The molar mass of \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\) is \(\boxed{149.1 \, \text{g/mol}}\).

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