Questions: Find the correct graph of the equation.
y=-(x+2)^2-4
Choose the correct graph on the right.
Transcript text: 3: timed test \& 1 attempt
Question 6 of 12
Find the correct graph of the equation.
\[
y=-(x+2)^{2}-4
\]
Choose the correct graph on the right.
Solution
Solution Steps
To find the correct graph of the equation \( y = -(x+2)^2 - 4 \), we need to understand the transformation of the basic parabola \( y = x^2 \). The equation involves a horizontal shift, a vertical shift, and a reflection. Specifically, the graph is shifted 2 units to the left, 4 units down, and is reflected over the x-axis. We can plot this equation to visualize the graph.
To solve the problem of finding the correct graph of the equation \( y = -(x+2)^2 - 4 \), we will analyze the equation step by step.
Step 1: Identify the Type of Equation
The given equation is a quadratic equation in the form of a parabola. The general form of a parabola is \( y = a(x-h)^2 + k \), where \((h, k)\) is the vertex of the parabola.
Step 2: Determine the Vertex
The equation \( y = -(x+2)^2 - 4 \) can be rewritten in the vertex form:
The term \((x+2)\) indicates a horizontal shift to the left by 2 units.
The constant \(-4\) indicates a vertical shift downward by 4 units.
Thus, the vertex of the parabola is \((-2, -4)\).
Step 3: Determine the Direction of the Parabola
The coefficient of the \((x+2)^2\) term is \(-1\), which is negative. This means the parabola opens downwards.
Step 4: Sketch the Graph
Based on the analysis:
The vertex is at \((-2, -4)\).
The parabola opens downwards.
The graph should show a parabola with its vertex at \((-2, -4)\) and opening downwards.
Final Answer
The correct graph of the equation \( y = -(x+2)^2 - 4 \) is a downward-opening parabola with its vertex at \((-2, -4)\).
\(\boxed{\text{The graph is a downward-opening parabola with vertex } (-2, -4).}\)