Questions: Refer to Exhibit 1. The percentage of workers who took 1 - 5 sick days per month was (A) 20% (B) 60% (C) 75% (D) 120%

Solution Steps

To find the total number of workers, we sum the frequencies of sick days taken:

\[ \text{Total Workers} = 0 + 120 + 14 + 1 = 135 \]

The frequency of workers who took 1-5 sick days is calculated by subtracting the known frequencies from the total:

\[ \text{Frequency for } 1-5 \text{ days} = \text{Total Workers} - (\text{Frequency for } 6-10 + \text{Frequency for } 11-15 + \text{Frequency for } 16-20) \]

Substituting the values:

\[ \text{Frequency for } 1-5 \text{ days} = 135 - (120 + 14 + 1) = 135 - 135 = 0 \]

The percentage of workers who took 1-5 sick days is given by:

\[ \text{Percentage} = \left( \frac{\text{Frequency for } 1-5 \text{ days}}{\text{Total Workers}} \right) \times 100 \]

Substituting the values:

\[ \text{Percentage} = \left( \frac{0}{135} \right) \times 100 = 0.00\% \]

Given the calculated percentage of \(0.00\%\), we compare it with the provided options:

• (A) \(20\%\)
• (B) \(60\%\)
• (C) \(75\%\)
• (D) \(120\%\)

Since \(0.00\%\) does not match any of the options, we conclude that the answer is not among the provided choices.

Final Answer