Questions: Unit Exam - Populations r = (CBR + IMA) - (CDR + EM) CBR = 1% IMA = 1% CDR = 1% EM = 3% What is r? -2% 4% 6%

Transcript text: Unit Exam - Populations \[ \begin{array}{c} r=(C B R+I M A)-(C D R+E M) \\ C B R=1 \% \quad I M A=1 \% \\ C D R=1 \% \quad E M=3 \% \end{array} \] What is $r$ ? $-2 \%$ $4 \%$ $6 \%$

Solution

Solution Steps

To find $ r $, we need to substitute the given values into the formula and perform the arithmetic operations.

Substitute $ CBR = 1\% $, $ IMA = 1\% $, $ CDR = 1\% $, and $ EM = 3\% $ into the formula $ r = (CBR + IMA) - (CDR + EM) $.
Calculate the sum of $ CBR $ and $ IMA $.
Calculate the sum of $ CDR $ and $ EM $.
Subtract the second sum from the first sum to get $ r $.

Step 1: Substitute Values

We start with the formula for $ r $: \[ r = (CBR + IMA) - (CDR + EM) \] Substituting the given values: \[ CBR = 1\%, \quad IMA = 1\%, \quad CDR = 1\%, \quad EM = 3\% \] we have: \[ r = (1 + 1) - (1 + 3) \]

Step 2: Calculate Sums

Now, we calculate the sums: \[ CBR + IMA = 1 + 1 = 2 \] \[ CDR + EM = 1 + 3 = 4 \]

Step 3: Compute $ r $

Next, we compute $ r $: \[ r = 2 - 4 = -2 \]