Questions: H2O2 contains equal parts by weight of hydrogen and oxygen. (A) True (B) False

Solution Steps

First, we need to calculate the molecular weight of hydrogen peroxide ($\mathrm{H}_{2}\mathrm{O}_{2}$). The molecular weight is the sum of the atomic weights of all atoms in the molecule.

• The atomic weight of hydrogen (H) is approximately 1.008.
• The atomic weight of oxygen (O) is approximately 16.00.

The molecular weight of $\mathrm{H}_{2}\mathrm{O}_{2}$ is: \[ 2 \times 1.008 + 2 \times 16.00 = 2.016 + 32.00 = 34.016 \]

Next, we calculate the weight contribution of hydrogen and oxygen in the molecule.

• The weight contribution of hydrogen is: \[ \frac{2 \times 1.008}{34.016} \approx \frac{2.016}{34.016} \approx 0.0593 \text{ or } 5.93\% \]

• The weight contribution of oxygen is: \[ \frac{2 \times 16.00}{34.016} \approx \frac{32.00}{34.016} \approx 0.9407 \text{ or } 94.07\% \]

From the calculations, it is clear that hydrogen and oxygen do not contribute equally to the weight of $\mathrm{H}_{2}\mathrm{O}_{2}$. Hydrogen contributes approximately 5.93%, while oxygen contributes approximately 94.07%.

Final Answer